Syntax error Check if right triangle possible from given area and hypotenuse in Python

Check if right triangle possible from given area and hypotenuse in Python

Suppose we have the hypotenuse and area of a right angle triangle, we have to find the base and height of this triangle. If it is not possible return False.

So, if the input is like hypo = 10, area = 24, then the output will be (6, 8).

To solve this, we will follow these steps −

  • hypo_sq := hypo * hypo
  • s := square root of (hypo_sq / 2.0)
  • maxArea := calculate area of triangle using base s and hypotenuse hypo
  • if area > maxArea, then
    • return False
  • left := 0.0, right := s
  • while |right - left| > 0.000001, do
    • base := (left + right) / 2.0
    • if area of triangle using base s and hypotenuse hypo >= area, then
      • right := base
    • otherwise,
      • left := base
  • height := square root of (hypo_sq - base*base) and round of to nearest integer
  • round of to nearest integer of base
  • return base and height

Let us see the following implementation to get better understanding −

Example Code

Live Demo

from math import sqrt
 
def calculate_area(b, h):
   hei = sqrt(h*h - b*b);
   return 0.5 * b * hei

def solve(hypo, area):
   hypo_sq = hypo * hypo
   s = sqrt(hypo_sq / 2.0)
   maxArea = calculate_area(s, hypo)

   if area > maxArea:
      return False
     
   left = 0.0
   right = s
     
   while abs(right - left) > 0.000001:
      base = (left + right) / 2.0
      if calculate_area(base, hypo) >= area:
         right = base
      else:
         left = base
     
   height = round(sqrt(hypo_sq - base*base))
   base = round(base)
   return base, height

hypo = 10
area = 24
print(solve(hypo, area))

Input

10, 24

Output

(6, 8)
Updated on: 2021-01-15T06:15:15+05:30

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