Fetch domain name by passing name in MySQL?

To fetch domain name by passing name in MySQL, you can use substring_index(). Let us first create a table −

mysql> create table DemoTable
   (
   UserId int NOT NULL AUTO_INCREMENT PRIMARY KEY,
   UserMailId varchar(200)
   );
Query OK, 0 rows affected (0.77 sec)

Insert some records in the table using insert command −

mysql> insert into DemoTable(UserMailId) values('John9989@facebook.com');
Query OK, 1 row affected (0.18 sec)

mysql> insert into DemoTable(UserMailId) values('983773CS@yahoo.com');
Query OK, 1 row affected (0.23 sec)

mysql> insert into DemoTable(UserMailId) values('Chris95@gmail.com');
Query OK, 1 row affected (0.20 sec)

Display all records from the table using select statement −

mysql> select *from DemoTable;

This will produce the following output −

+--------+-----------------------+
| UserId | UserMailId            |
+--------+-----------------------+
|      1 | John9989@facebook.com |
|      2 | 983773CS@yahoo.com    |
|      3 | Chris95@gmail.com     |
+--------+-----------------------+
3 rows in set (0.00 sec)

Following is the query to fetch domain name by passing name in MySQL.

mysql> select
   UserId,UserMailId,
   substring_index(substring_index(UserMailId, '@', -1), '.', 1) AS `Domain_Name`
   from DemoTable;

This will produce the following output. Here, domain name is fetched −

+--------+-----------------------+-------------+
| UserId | UserMailId            | Domain_Name |
+--------+-----------------------+-------------+
|      1 | John9989@facebook.com | facebook    |
|      2 | 983773CS@yahoo.com    | yahoo       |
|      3 | Chris95@gmail.com     | gmail       |
+--------+-----------------------+-------------+
3 rows in set (0.01 sec)

Smita Kapse

Updated on: 2019-07-30T22:30:26+05:30

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