Syntax error Get the average of an entire field using the aggregation framework in MongoDB?

Get the average of an entire field using the aggregation framework in MongoDB?

You can use aggregate() method for this. Let us first create a collection with documents

> db.averageAggregationDemo.insertOne({"PlayerGameScore":45});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5c9ed66bd628fa4220163b95")
}
> db.averageAggregationDemo.insertOne({"PlayerGameScore":55});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5c9ed671d628fa4220163b96")
}
> db.averageAggregationDemo.insertOne({"PlayerGameScore":65});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5c9ed676d628fa4220163b97")
}
> db.averageAggregationDemo.insertOne({"PlayerGameScore":35});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5c9ed67bd628fa4220163b98")
}
> db.averageAggregationDemo.insertOne({"PlayerGameScore":16});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5c9ed701d628fa4220163b99")
}

Following is the query to display all documents from a collection with the help of find() method

> db.averageAggregationDemo.find().pretty();

This will produce the following output

{ "_id" : ObjectId("5c9ed66bd628fa4220163b95"), "PlayerGameScore" : 45 }
{ "_id" : ObjectId("5c9ed671d628fa4220163b96"), "PlayerGameScore" : 55 }
{ "_id" : ObjectId("5c9ed676d628fa4220163b97"), "PlayerGameScore" : 65 }
{ "_id" : ObjectId("5c9ed67bd628fa4220163b98"), "PlayerGameScore" : 35 }
{ "_id" : ObjectId("5c9ed701d628fa4220163b99"), "PlayerGameScore" : 16 }
Following is the query to get the average of an entire field with aggregation:
> db.averageAggregationDemo.aggregate({ "$group": { "_id": null, "PlayerGameScoreAverage": { "$avg": "$PlayerGameScore" } } } );

This will produce the following output

{ "_id" : null, "PlayerGameScoreAverage" : 43.2 }
Updated on: 2019-07-30T22:30:25+05:30

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