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Grouping the array items in MongoDB and get the count the products with similar price?
To group the array items, use $group along with $sort. Let us create a collection with documents −
> db.demo566.insertOne(
... {
...
... "ProductInformation" : [
... {
... "ProductName" : "Product-1",
... "ProductPrice" :100
... },
... {
... "ProductName" : "Product-2",
... "ProductPrice" :1100
... },
... {
... "ProductName" : "Product-3",
... "ProductPrice" :100
... },
... {
... "ProductName" : "Product-4",
... "ProductPrice" :1100
... },
... {
... "ProductName" : "Product-5",
... "ProductPrice" :100
... }
... ]
...
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5e908e2339cfeaaf0b97b57a")
}
Display all documents from a collection with the help of find() method −
> db.demo566.find();
This will produce the following output −
{ "_id" : ObjectId("5e908e2339cfeaaf0b97b57a"), "ProductInformation" : [
{ "ProductName" : "Product-1", "ProductPrice" : 100 },
{ "ProductName" : "Product-2", "ProductPrice" : 1100 },
{ "ProductName" : "Product-3", "ProductPrice" : 100 },
{ "ProductName" : "Product-4", "ProductPrice" : 1100 },
{ "ProductName" : "Product-5", "ProductPrice" : 100 }
] }
Following is the query to group the array items −
> db.demo566.aggregate([
... {
... "$unwind": "$ProductInformation"
... },
... {
... "$group": {
... "_id": "$ProductInformation.ProductPrice",
... "Value": { "$sum" : 1 }
... }
... },
... { "$sort": { "_id" :1 } }
... ])
This will produce the following output −
{ "_id" : 100, "Value" : 3 }
{ "_id" : 1100, "Value" : 2 }
Updated on: 2020-05-14T08:33:48+05:30
927 Views
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