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How to display the count from distinct records in the same row with MySQL?
For this, you can use GROUP_CONCAT(), COUNT() along with GROUP BY clause. Let us first create a table −
mysql> create table DemoTable -> ( -> CompanyId int NOT NULL AUTO_INCREMENT PRIMARY KEY, -> CompanyName varchar(20) -> ); Query OK, 0 rows affected (0.62 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable(CompanyName) values('Amazon');
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable(CompanyName) values('Google');
Query OK, 1 row affected (0.09 sec)
mysql> insert into DemoTable(CompanyName) values('Google');
Query OK, 1 row affected (0.07 sec)
mysql> insert into DemoTable(CompanyName) values('Microsoft');
Query OK, 1 row affected (0.17 sec)
mysql> insert into DemoTable(CompanyName) values('Amazon');
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable(CompanyName) values('Amazon');
Query OK, 1 row affected (0.07 sec)
Display all records from the table using select statement −
mysql> select *from DemoTable;
This will produce the following output−
+-----------+-------------+ | CompanyId | CompanyName | +-----------+-------------+ | 1 |Amazon | | 2 |Google | | 3 |Google | | 4 |Microsoft | | 5 |Amazon | | 6 |Amazon | +-----------+-------------+ 6 rows in set (0.00 sec)
Here is the query to display the count from distinct records in the same row with MySQL −
mysql> select CompanyName,group_concat(CompanyId),count(CompanyId) as count from DemoTable -> group by CompanyName -> having count > 1;
This will produce the following output −
+-------------+-------------------------+-------+ | CompanyName | group_concat(CompanyId) | count | +-------------+-------------------------+-------+ | Amazon | 1,5,6 | 3 | | Google | 2,3 | 2 | +-------------+-------------------------+-------+ 2 rows in set (0.00 sec)
Updated on: 2019-12-12T06:03:12+05:30
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