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How to use MySQL LIKE clause to fetch multiple values beginning with “Joh”
Let us first create a table −
mysql> create table DemoTable ( Name varchar(40) ); Query OK, 0 rows affected (0.55 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable values('John');
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable values('Sam');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable values('Mike');
Query OK, 1 row affected (0.11 sec)
mysql> insert into DemoTable values('Ethan');
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable values('Johnson');
Query OK, 1 row affected (0.16 sec)
mysql> insert into DemoTable values('Bob');
Query OK, 1 row affected (0.12 sec)
Display all records from the table using select statement −
mysql> select *from DemoTable;
This will produce the following output −
+---------+ | Name | +---------+ | John | | Sam | | Mike | | Ethan | | Johnson | | Bob | +---------+ 6 rows in set (0.00 sec)
Following is the query to fetch multiple values beginning with “Joh” −
mysql> select *from( select Name as myValue from DemoTable union select Name from DemoTable )tbl where myValue like 'Joh%';
This will produce the following output −
+---------+ | myValue | +---------+ | John | | Johnson | +---------+ 2 rows in set (0.00 sec)
Updated on: 2019-10-07T11:47:15+05:30
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