Syntax error Java Program to multiply integers and check for overflow

Java Program to multiply integers and check for overflow

To check for Integer overflow, we need to check the Integer.MAX_VALUE with the multiplied integers result, Here, Integer.MAX_VALUE is the maximum value of an integer in Java.

Let us see an example wherein integers are multiplied and if the result is more than the Integer.MAX_VALUE, then an exception is thrown.

The following is an example showing how to check for Integer overflow.

Example

 Live Demo

public class Demo {
   public static void main(String[] args) {
      int val1 = 9898;
      int val2 = 6784;
      System.out.println("Value1: "+val1);
      System.out.println("Value2: "+val2);
      long mul = (long)val1 * (long)val2;
      if (mul > Integer.MAX_VALUE) {
         throw new ArithmeticException("Overflow!");
      }
      // displaying multiplication
      System.out.println("Multiplication Result: "+(int)mul);
   }
}

Output

Value1: 9898
Value2: 6784
Multiplication Result: 67148032

In the above example, we have taken the following two integers.

int val1 = 9898;
int val2 = 6784;

Now we will cast and multiply them to a long.

long mul = (long)val1 + (long)val2;

If the result is more than the maximum value, then an exception is thrown.

If (mul > Integer.MAX_VALUE) {
   throw new ArithmeticException("Overflow!");
}
Updated on: 2020-06-26T10:14:54+05:30

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