- Trending Categories
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Maximum product from array such that frequency sum of all repeating elements in product is less than or equal to 2 * k in C++
In this tutorial, we will be discussing a program to find maximum product from array such that frequency sum of all repeating elements in product is less than or equal to 2 * k.
For this we will be provided with an array and an integer k. Our task is to find the maximum product from the array given that the frequency sum of all digits must be smaller than or equal to 2 * k.
Example
#include <bits/stdc++.h>
using namespace std;
#define ll long long int
//returning maximum product value
ll maxProd(int arr[], int n, int k) {
ll product = 1;
unordered_map<int, int> s;
sort(arr, arr + n);
for (int i = 0; i < n; i++) {
if (s[arr[i]] == 0) {
product = product * arr[i];
}
//storing values in hash map
s[arr[i]] = s[arr[i]] + 1;
}
for (int j = n - 1; j >= 0 && k > 0; j--) {
if ((k > (s[arr[j]] - 1)) && ((s[arr[j]] - 1) > 0)){
product *= pow(arr[j], s[arr[j]] - 1);
k = k - s[arr[j]] + 1;
s[arr[j]] = 0;
}
if (k <= (s[arr[j]] - 1) && ((s[arr[j]] - 1) > 0)) {
product *= pow(arr[j], k);
break;
}
}
return product;
}
int main() {
int arr[] = { 5, 6, 7, 8, 2, 5, 6, 8 };
int n = sizeof(arr) / sizeof(arr[0]);
int k = 2;
cout << maxProd(arr, n, k);
return 0;
}
Output
161280
Updated on: 2020-09-09T12:50:50+05:30
131 Views
Advertisements