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MongoDB aggregate to convert multiple documents into single document with an array?
For aggregate in MongoDB, use aggregate(). Let us create a collection with documents −
> db.demo248.insertOne({"id":101,"Name":"Chris","Age":21,"CountryName":"US"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e46b6651627c0c63e7dba6d")
}
> db.demo248.insertOne({"id":101,"Name":"Bob","Age":22,"CountryName":"UK"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e46b6741627c0c63e7dba6e")
}
> db.demo248.insertOne({"id":102,"Name":"Mike","Age":20,"CountryName":"AUS"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e46b6811627c0c63e7dba6f")
}
Display all documents from a collection with the help of find() method −
> db.demo248.find();
This will produce the following output −
{ "_id" : ObjectId("5e46b6651627c0c63e7dba6d"), "id" : 101, "Name" : "Chris", "Age" : 21, "CountryName" : "US" }
{ "_id" : ObjectId("5e46b6741627c0c63e7dba6e"), "id" : 101, "Name" : "Bob", "Age" : 22, "CountryName" : "UK" }
{ "_id" : ObjectId("5e46b6811627c0c63e7dba6f"), "id" : 102, "Name" : "Mike", "Age" : 20, "CountryName" : "AUS" }
Following is the query to convert multiple documents into single document with an array −
> db.demo248.aggregate([
... {
... $group : {
... _id : "$id",
... details : {
... $push : {
... id:"$id",
... Name:"$Name",
... Age:"$Age",
... CountryName:"$CountryName"
... }
... }
... }
... }
...])
This will produce the following output −
{ "_id" : 102, "details" : [ { "id" : 102, "Name" : "Mike", "Age" : 20, "CountryName" : "AUS" } ] }
{ "_id" : 101, "details" : [ { "id" : 101, "Name" : "Chris", "Age" : 21, "CountryName" : "US" }, { "id" : 101, "Name" : "Bob", "Age" : 22, "CountryName" : "UK" } ] }
Updated on: 2020-03-30T14:09:09+05:30
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