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MongoDB query to filter only the logs containing the “work” word in the content
To filter the logs containing the word “work” , use aggregate() along with $filter. Let us first create a collection with documents −
> db.demo383.insertOne(
... {
... "ServerName":"Jboss",
... "ServerLogs": [
... {
... "status":"Working"
... },
... {
... "status":"Stop"
... },
... {
... "status":"Worked"
... }
... ]
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5e5b635422064be7ab44e7f1")
}
Display all documents from a collection with the help of find() method −
> db.demo383.find().pretty();
This will produce the following output −
{
"_id" : ObjectId("5e5b635422064be7ab44e7f1"),
"ServerName" : "Jboss",
"ServerLogs" : [
{
"status" : "Working"
},
{
"status" : "Stop"
},
{
"status" : "Worked"
}
]
}
Following is the query to filter −
> db.demo383.aggregate([
... { "$addFields": {
... "ServerLogs": {
... "$filter": {
... "input": "$ServerLogs",
... "cond": {
... "$ne": [
... { "$indexOfBytes": [
... { "$toUpper": "$$this.status" },
... { "$toUpper": "work" }
... ]},
... -1
... ]
... }
... }
... }
... }}
... ])
This will produce the following output −
{
"_id" : ObjectId("5e5b635422064be7ab44e7f1"), "ServerName" : "Jboss", "ServerLogs" : [
{ "status" : "Working" }, { "status" : "Worked" }
]
}
Updated on: 2020-04-02T13:41:52+05:30
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