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MySQL query to display records ordered by numeric difference?
Use ORDER BY and set the difference to display records ordered by numeric difference. Following is the syntax −
select *from yourTableName order by (yourIntegerColumnName1 - yourIntegerColumnName2);
Let us first create a table −
mysql> create table DemoTable1313 -> ( -> Name varchar(20), -> Score1 int, -> Score2 int -> ); Query OK, 0 rows affected (3.48 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable1313 values('Chris',40,60);
Query OK, 1 row affected (0.38 sec)
mysql> insert into DemoTable1313 values('David',70,50);
Query OK, 1 row affected (0.16 sec)
mysql> insert into DemoTable1313 values('Adam',35,30);
Query OK, 1 row affected (0.18 sec)
Display all records from the table using select statement −
mysql> select *from DemoTable1313;
Output
+-------+--------+--------+ | Name | Score1 | Score2 | +-------+--------+--------+ | Chris | 40 | 60 | | David | 70 | 50 | | Adam | 35 | 30 | +-------+--------+--------+ 3 rows in set (0.00 sec)
Following is the query to order by numeric difference −
mysql> select *from DemoTable1313 -> order by (Score1-Score2);
Output
+-------+--------+--------+ | Name | Score1 | Score2 | +-------+--------+--------+ | Chris | 40 | 60 | | Adam | 35 | 30 | | David | 70 | 50 | +-------+--------+--------+ 3 rows in set (0.00 sec)
Updated on: 2019-11-04T10:46:31+05:30
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