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MySQL query to order and display difference between dates from the current date
For this, use ORDER BY clause. The current date is as follows −
mysql> select now(); +---------------------+ | now() | +---------------------+ | 2019-06-09 21:08:16 | +---------------------+ 1 row in set (0.00 sec)
Let us first create a table −
mysql> create table DemoTable -> ( -> Id int NOT NULL AUTO_INCREMENT PRIMARY KEY, -> DueDate datetime -> ); Query OK, 0 rows affected (0.62 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable(DueDate) values('2019-06-12');
Query OK, 1 row affected (0.24 sec)
mysql> insert into DemoTable(DueDate) values('2019-06-01');
Query OK, 1 row affected (0.37 sec)
mysql> insert into DemoTable(DueDate) values('2019-06-05');
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable(DueDate) values('2019-06-10');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable(DueDate) values('2019-06-11');
Query OK, 1 row affected (0.66 sec)
Display all records from the table using select statement −
mysql> select *from DemoTable;
Output
+----+---------------------+ | Id | DueDate | +----+---------------------+ | 1 | 2019-06-12 00:00:00 | | 2 | 2019-06-01 00:00:00 | | 3 | 2019-06-05 00:00:00 | | 4 | 2019-06-10 00:00:00 | | 5 | 2019-06-11 00:00:00 | +----+---------------------+ 5 rows in set (0.00 sec)
Here is the query to order by to get the difference and order the dates. The difference between the dates are displayed in a separate column −
mysql> select Id,DueDate,DATEDIFF(DueDate, CURDATE()) AS t from DemoTable -> order by CASE WHEN t < 0 THEN 1 ELSE 0 END, t;
Output
+----+---------------------+------+ | Id | DueDate | t | +----+---------------------+------+ | 4 | 2019-06-10 00:00:00 | 1 | | 5 | 2019-06-11 00:00:00 | 2 | | 1 | 2019-06-12 00:00:00 | 3 | | 2 | 2019-06-01 00:00:00 | -8 | | 3 | 2019-06-05 00:00:00 | -4 | +----+---------------------+------+ 5 rows in set (0.00 sec)
Updated on: 2019-07-30T22:30:26+05:30
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