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MySQL query to return the count of only NO values from corresponding column value
Let us first create a table −
mysql> create table DemoTable1829
(
Name varchar(20),
isTopper ENUM('YES','NO')
);
Query OK, 0 rows affected (0.00 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable1829 values('Chris','yes');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1829 values('David','yes');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1829 values('Mike','no');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1829 values('David','yes');
Query OK, 1 row affected (0.00 sec)
Display all records from the table using select statement −
mysql> select * from DemoTable1829;
This will produce the following output −
+-------+----------+ | Name | isTopper | +-------+----------+ | Chris | YES | | David | YES | | Mike | NO | | David | YES | +-------+----------+ 4 rows in set (0.00 sec)
Here is the query to return the count of only NO values −
mysql> select Name,sum(isTopper='no') from DemoTable1829 group by Name;
This will produce the following output −
+-------+--------------------+ | Name | sum(isTopper='no') | +-------+--------------------+ | Chris | 0 | | David | 0 | | Mike | 1 | +-------+--------------------+ 3 rows in set (0.00 sec)
Updated on: 2019-12-24T07:45:54+05:30
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