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Using count equivalent in MongoDB to find top users with max occurrence
To get the count and top users, use $group along with aggregate() . Let us create a collection with documents −
> db.demo264.insertOne({"Name":"Chris"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e47ed441627c0c63e7dba9e")
}
> db.demo264.insertOne({"Name":"David"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e47ed471627c0c63e7dba9f")
}
> db.demo264.insertOne({"Name":"Chris"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e47ed491627c0c63e7dbaa0")
}
> db.demo264.insertOne({"Name":"Bob"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e47ed4c1627c0c63e7dbaa1")
}
> db.demo264.insertOne({"Name":"Chris"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e47ed4e1627c0c63e7dbaa2")
}
> db.demo264.insertOne({"Name":"Bob"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e47ed531627c0c63e7dbaa3")
}
Display all documents from a collection with the help of find() method −
> db.demo264.find();
This will produce the following output −
{ "_id" : ObjectId("5e47ed441627c0c63e7dba9e"), "Name" : "Chris" }
{ "_id" : ObjectId("5e47ed471627c0c63e7dba9f"), "Name" : "David" }
{ "_id" : ObjectId("5e47ed491627c0c63e7dbaa0"), "Name" : "Chris" }
{ "_id" : ObjectId("5e47ed4c1627c0c63e7dbaa1"), "Name" : "Bob" }
{ "_id" : ObjectId("5e47ed4e1627c0c63e7dbaa2"), "Name" : "Chris" }
{ "_id" : ObjectId("5e47ed531627c0c63e7dbaa3"), "Name" : "Bob" }
Following is the query to use count equivalent in MongoDB to find top users with max occurrence −
> db.demo264.aggregate(
... {$group : {_id : "$Name", "count" : {$sum : 1}}},
... {$sort : {"count" : -1}},
... {$limit : 5}
...)
This will produce the following output −
{ "_id" : "Chris", "count" : 3 }
{ "_id" : "Bob", "count" : 2 }
{ "_id" : "David", "count" : 1 }
Updated on: 2020-03-31T08:36:07+05:30
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