Area Calculation - Online Quiz



Following quiz provides Multiple Choice Questions (MCQs) related to Area Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - How numerous meters of floor covering 63cm wide will be required to cover the floor of a room 14m by 9m?

A - 200 m

B - 210 m

C - 220 m

D - 185 m

Answer : A

Explanation

Width of the carpet = 63/100m. Let its length be x mtr.
Then, x*63/100=14*9 =x= (14*9*100/63) = 200m
∴length = 200 m

Q 2 - The aggregate expense of deck a room at rs.8.50 per square meter is Rs. 510. In the event that the length of the room is 8m, its expansiveness is:

A - 7.5 m

B - 8.5 m

C - 10.5 m

D - 12.5 m

Answer : A

Explanation

Area = total cost/rate =(510/8.50)m2= (510*2/17)m2= 60m2
Area =60m2, Length= 8m
Breadth =Area/ Length = 60/8m =7.5 m

Q 3 - The length of a rectangular plot is expanded by 25%. To keep its region unaltered, the width of the plot ought to be:

A - kept unaltered

B - expanded by 25%

C - expanded by 20%

D - Diminished by 20%

Answer : D

Explanation

Let the length be x meter and breadth be y mtr.
Then, its area = (xy) m2
New length = (125/100*x) m = (5x/4) m. let the new breadth be z meters.
Then, xy = 5x/4*z ⇒z= 4/5 y
Decrease in width = (y-4/5y) = y/5 mtr.
Decrease % in width = (y/5*1/y*100) % = 20%

Q 4 - A rectangle has 15cm as its length and 150cm2 as its area. Its territory is expanded to 4/3 times the first region by expanding just its length. Its new border is:

A - 50 cm

B - 60 cm

C - 70 cm

D - 80 cm

Answer : B

Explanation

Length = 15cm, area = 150cm2.
Breadth = 150/15 cm = 10cm
New length = 200/10 cm = 20cm
New perimeter = 2(20+10) cm = 60 cm

Q 5 - The area of the largest circle that can be drawn insight rectangle with sides 8m by 7m is:

A - 352m2/7

B - 77/2m2

C - 32m2

D - 49m2

Answer : B

Explanation

Radius of the circle= 7/2 m
Area of the circle = (22/7 *7/2 *7/2) m2 =77/2m2

Q 6 - A circle and a rectangle have same perimeter.The side of the rectangle is 18cm and 26 cm. what is the area of the circle?

A - 88 cm2

B - 154 cm2

C - 616 cm2

D - 1250 cm2

Answer : C

Explanation

Circumference of the circle= Perimeter of the rectangle
= 2 (18+26) cm= 88cm
2*22/7* R= 88 ⇒ R= (88*7/44) =14 cm
Area of the circle = πr2 = (22/7 *14*14) cm2 =616 cm2

Q 7 - The perimeter of a square and that of an equilateral triangle are equal. If the length of diagonal of the square be 12 √2cm, then area of the triangle is:

A - 64√3 cm2

B - 32√3 cm2

C - 24√3 cm2

D - 24√2 cm2

Answer : A

Explanation

Let each side of the square be a cm.
Then, its diagonal= √2A cm.
∴ √2 A= 12 √2 ⇒ A = 12.
Perimeter of the triangle= Perimeter of the square = (12*4) =48 cm
Each side of the triangle =48/3= 16 cm
Area of the triangle = (√3/4* 16*16) cm2= 64√3 cm2

Q 8 - The territory of a circle engraved in an equilateral triangle is 462 cm2. The edge of this triangle is:

A - 42√3 cm

B - 72.6 cm

C - 126 cm

D - 168 cm

Answer : C

Explanation

Πr2 = 462 ⇒ 22/7* r2 = 462 ⇒ r2 = (462*7/22) = 147
⇒ r = √ 7*7*3   = 7 √3  cm
Height = 3r = (3* 7 √ 3) cm   = 21√ 3 cm
a2 - (a/2) 2 = (21√ 3) 2 ⇒ (a2- a2/4) = 1323
3a2 = (1323*4) ⇒   a2= (441* 4) ⇒ a = (21*2) = 42
Perimeter of the triangle = 3a = (3*42) = 126 cm.

Q 9 - Each side of an equilateral triangle is equivalent to the span of a circle whose region is 154 cm2. The range of the equilateral triangle is:

A - 7√3/4 cm2

B - 49√3/4 cm2

C - 35 cm2

D - 49cm2

Answer : B

Explanation

Let each side of the equilateral triangle be a cm and radius of the circle is r cm.  Then , a =r
πr2 =154 ⇒22/7 *r2=154⇒ r 2= (154*7/22) = 49 ⇒r= 7
∴ a = 7cm ⇒ area of ∆ = √ 3/4 *(7)2 cm2=49√3/4 cm2

Q 10 - A round greenery enclosure has an outline of 440 m. There is a 7m wide fringe inside the patio nursery along its outskirts. The territory of the fringe is:

A - 2918m2

B - 2921 m2

C - 2924 m2

D - 2926 m2

Answer : D

Explanation

2πR =440 ⇒ 2*22/7*R= 440 ⇒R= (440* 7/44)=70 m
Outer radius = 70m, inner radius = (70-7) =63 m
Required area = π [(70)2-(63)2] m2= 22/7 *(70+63) (70-63) m2
= (22*133) m2, = 2926m2
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