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Chain Rules - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Chain Rules. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - If 21 cows eat as much as 15 buffaloes, how many cows will eat as much as 35 buffaloes?
Answer : A
Explanation
15 buffaloes = 21 cows ⇒ 1 buffalo = 21/15 cows = 7/5 cows ⇒35 buffaloes = (35 * 7/5 ) cows = 49 cows.
Q 2 - 10 men can finish the construction of a wall in 8 days. How many men are added to finish the work in half a day?
Answer : D
Explanation
Let the total number of men be x. Less days , more men required (Indirect) 1/2 : 8 :: 10 : x ⇒ 1/2 x =(8* 10 )⇒ x= (8* 10* 2*) = 160. Number of men to be added = (160- 10 )=150.
Q 3 - 8 men can complete a piece of work in 12 days ; 4 women can complete it in 48 days and 10 children can complete the same piece of work in 24 days . In how many days can 10 men , 4 women and 10 children complete the same piece of work?
Answer : D
Explanation
1 man can complete the work in ( 12 * 8) = 96 days. 1 women can complete the work in ( 48 * 4) = 192 days. 1 child can complete the work in ( 24 * 10) = 240 days. 1 men 1 days work = 1/96, 1 women1 days work = 1/192. 1 child 1 days work = 1/240. ( 10 men + 4 women + 10 children) 1 days work = ( 10/ 96 + 4/192 + 10/240) = (5/48 + 1 /48 + 1/24) = 8/48 = 1/6. ∴ They will do the work in 6 days.
Q 4 - 8 men and 12 children can do a piece of work in 9 days . A child takes double the time to do a work than the men. In how many days 12 men can complete the work?
Answer : A
Explanation
2 children = 1 men ⇒ (8 men + 12 children ) = 14 men. Let the required number of days be x. Less men , more day (Indirect ) 12 : 14:: 9 : x ⇒ 12x = ( 14 * 90 ⇒ ( 14* 9 ) /12 = 21 /2 = 21/2 days.
Q 5 - In a barrack of soldiers there was stock of food for 190 days for 4000 soldiers.After 30 days , 800 soldiers left the barrack. For how many days shall the left over Food last for the remaining soldiers?
Answer : B
Explanation
Remaining food was sufficient for 4000 soldiers for 160 days. Remaining soldiers = ( 4000- 800) = 3200. Let the required number of days be x . Less soldiers, more days (Indirect) 3200 : 4000 :: 160 : x⇒ 3200 x = (4000 * 160 ) ⇒ x = (4000 * 160)/3200 = 200 days.
Q 6 - A garrison of 500 men had provisions for 27 days. After 3 days ,a reinforcement of 300 men arrived. The remaining food will now last for how many days
Answer : A
Explanation
500 men had provisions for (27-3) = 24 days . Let the food for 800 men last for x days. More men , less days (Indirect) 800: 500 :: 24 : x ⇒ 800x = (500 * 24 ) ⇒ x = (500 * 24)/800 = 15 days.
Q 7 - If 6 persons working 8 hours a day earn Rs 16800 per week , then 9 persons working 6 hours a day will earn per week?
Answer : B
Explanation
Let the required earning be Rs x. More persons , more earning ( Direct) Less hrs per day, less earning ( Direct) Persons 6:9 :: 16800 : x Hrs / day 8 : 6 (6 * 8 *x ) = ( 9 * 6 * 16800) = X =9 * 6 * 16800/ 6 *8 = 18900.
Q 8 - If the rent for grazing 40 cows for 20 days in Rs 740, how many cows can graze for 30 days on Rs 222?
Answer : B
Explanation
Let the required number of cows be x. Less rent, less cows (Direct) More days, less cows (Indirect) Rent 740 : 222 :: 40 : x Days 30: 20 ∴ ( 740 * 30 * x) = ( 222 * 20 * 40 ) ⇒ x = 222* 20 * 40 / 740 * 30 = 8 cows.
Q 9 - If a certain number of workmen can be a piece of work in 25 days , in what time will another set of an equal number of men do a piece of work twice as great , supposing that 2 of the first set can do as much work in an hour as 3 of the second set can do in an hour
Answer : B
Explanation
Let the required time be x days . Ratio of their speed = 1/2 : 1/3. More work , more time (Direct) Less speed, more work (Indirect) Work 1:2 :: 25:x Speed 1/3 : 1/2 ∴ (1* 1/3 *x) = 2 *1/2 *25 ⇒ x=75days.
Q 10 - A contractor undertakes to do a piece of work in 40 days . He engages 100 men at the beginning and 100 more after 35 days and complete the work in stipulated time. If he had not engaged the additional men, how many days behind schedule would it be finished?
Answer : A
Explanation
[(100 *35 ) + (200 *5)] men can finish the work in 1 day. 4500 men can finish it in 1 day ∴ men can finish it in 4500/100 days = 45 days. This is 5 days behind schedule.