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Chain Rules - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Chain Rules. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - A rope makes 140 rounds of the circumference of a cylinder, the radius of whose base is 14cm . How many times can it go rounds a cylinder with radius 20 cm?
Answer : C
Explanation
Let the required number of round be x. More radius , less round (Indirect) 20: 14: :: 140 : x ⇒ 20x = (14*140 ) ⇒ x = (14 * 140/20 = 98. Required number of round = 98.
Q 2 - 10 men can finish the construction of a wall in 8 days. How many men are added to finish the work in half a day?
Answer : D
Explanation
Let the total number of men be x. Less days , more men required (Indirect) 1/2 : 8 :: 10 : x ⇒ 1/2 x =(8* 10 )⇒ x= (8* 10* 2*) = 160. Number of men to be added = (160- 10 )=150.
Q 3 - 10 women can complete a piece of work in 8 days and 10 children take 12 days to complete it. How many days will 6 women and 3 children together take to complete the work?
Answer : C
Explanation
1 women can complete the work in ( 10 * 8) = 80 days. 1 child can complete the work in ( 10 * 12) = 120 days. 1 women 1 days work = 1/80, 1 child 1 days work = 1/120. ( 6women + 3 children) 1 days work = ( 6 * 1/80 + 3 * 1/120) = ( 3 /40 + 1/40 ) = 4/40=1/10. Required time 10 days.
Q 4 - A does half as much work as B in one- sixth of time. If together they take 10 days to complete the work, how much time shall B alone take to do it ?
Answer : B
Explanation
Suppose B takes x days to finish the work . Then , A takes x/6 days to finish half the work . ∴ A takes 2x / 6 = x/3 days to finish the work. 1/x + 3/x = 1/10 ⇒ 4/x = 1/10 ⇒ x= 40. Hence , B along takes 40 days to finish the work.
Q 5 - If 9 men working hours 15/2 hours a day can finish a work in 20 days , then how many days will be taken by 12 men , working 6 hours a day to finish the work . It is given that 2 men of latter type work as much as 3 men of former type?
Answer : C
Explanation
2 men of latter type = 3 men of former tyes. 12 men of latter type = (3/2 *12) = 18 men of former tyes. Let the required number of days be x. More men , less days (Indirect) Men 18 : 9 :: 20 : x Working hrs 6 : 15 /2 ∴ 18 *6 *x = 9 * 15/2 * 20 ⇒ x= 9 * 150/18 * 6 = 25/2 = 25/2 days.
Q 6 - Four examiners can examine a certain number of answer papers in 10 days by working for 5 hours a day. For how many hours in a day would 2 examiners have to work in order to examine twice the number of answer papers in 20 days?
Answer : D
Explanation
Let the number of hours per days be x.
More days, less hours per days ( Indirect)
Less examiners , more hours per days ( Indirect)
More Ans. Books , more hours per days ( direct)
Days 20 : 10
Examiners 2 : 4 :: 5 : x
Ans. Books 1 : 2
∴ (20 * 2 * 1 * x) = ( 10 * 4 * 2* 5 ) ⇒ x = 400 / 40 = 10 hrs per days.
Q 7 - If 6 persons working 8 hours a day earn Rs 16800 per week , then 9 persons working 6 hours a day will earn per week?
Answer : B
Explanation
Let the required earning be Rs x. More persons , more earning ( Direct) Less hrs per day, less earning ( Direct) Persons 6:9 :: 16800 : x Hrs / day 8 : 6 (6 * 8 *x ) = ( 9 * 6 * 16800) = X =9 * 6 * 16800/ 6 *8 = 18900.
Q 8 - In a hospital, there is a consumption of 1350 litres of milk for 70 patients for 30 days. How many patients will consume 1710 litres of milk in 28 days?
Answer : C
Explanation
Let the required number of patients be x . More milk, more patients (Direct) Less days , more patients (Indirect) Litres 1350:1710 ::70 : x Days 28 : 30 ∴ ( 1350 * 28 * x ) = ( 1710 * 30 * 70) ⇒ x= 1710 * 30 * 70/ ( 1350 * 28 ) = 95 patients.
Q 9 - A contractor employed 30 men to do a piece of work in 38 days. After 25 days he employed 5 men more and the work was finished one day earlier. How many days , he would have been behind , if he had not employed additional men?
Answer : A
Explanation
After 25 days , 35 men finish the remaining work in (38 - 25 - 1) = 12 days. 35 men can finish the remaining work in 12 days. 30 men can finish it in (12 * 35) /30 days = 14 days , i.e. 1 day behind.
Q 10 - A contractor undertakes to do a piece of work in 40 days . He engages 100 men at the beginning and 100 more after 35 days and complete the work in stipulated time. If he had not engaged the additional men, how many days behind schedule would it be finished?
Answer : A
Explanation
[(100 *35 ) + (200 *5)] men can finish the work in 1 day. 4500 men can finish it in 1 day ∴ men can finish it in 4500/100 days = 45 days. This is 5 days behind schedule.