Aptitude - Simple Interest Online Quiz



Following quiz provides Multiple Choice Questions (MCQs) related to Simple Interest. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - How crunch simple interest will Rs 2000 win in year and a half at 6% for every annum?

A - Rs 120

B - Rs 180

C - Rs 216

D - Rs 240

Answer : B

Explanation

S.I = Rs. (2000*18/12*6/100) = Rs. 180.

Q 2 - A sure whole is contributed on basic interest, if it trebles in 10 years, what is the rate of interest?

A - 18% p.a.

B - 20%p.a.

C - 22% p.a.

D - 25%p.a.

Answer : B

Explanation

Let the sum be Rs. x then, S.I = Rs. (3x-x) = rs. 2x
∴ x*R/100*10= 2x = R = 20% p.a.

Q 3 - x, y, z are three entireties of cash such that y is the simple interest on x and z is the basic on y for the same time and rate. Which of the accompanying is right?

A - xyz=1

B - z2=xy

C - x2 =yz

D - y2= zx

Answer : D

Explanation

y= S.I. On Rs. x = Rs. (x*R*T/100); z=S.I on Rs.  y = Rs. (y*r*t/100)
∴ y/z = x/y => y2= zx.

Q 4 - An aggregate of Rs 5000 was loaned mostly at 6% and incompletely at 9% basic interest. On the off chance that the aggregate yearly premium be Rs 390, the proportion in which the cash was loaned at given rates is:

A - 1:1

B - 1:2

C - 2:3

D - 3:2

Answer : C

Explanation

Let the money invested at the two rates be rs. x and Rs. (5000-x)
Then, (x*6/100*1) + (5000-x) *9/100*1 = 390
=> 3x/50 + 9(5000-x)/100 = 390
=> 6x+45000-9x = 39000 => 3x= 6000 => x= 2000.
Required ratio = 2000:3000= 2:3

Q 5 - Minimal number of year in which the simple interest on Rs.2600 at 20? 3% simple interest will be correct number of Rs. is:

A - 2 years

B - 3 years

C - 4 years

D - 5 years

Answer : B

Explanation

S.I = (2600*20/3*1/100*n), where n is the number of years.
= (520/3*n), n being a whole number with minimum value= 3

Q 6 - Amit invests a certain sum at 10% per annum simple interest. In how many years will it become 5 times?

A - 15 years

B - 20 years

C - 40 years

D - None of these

Answer : C

Explanation

We know,
R = 100(n - 1)/t
Or, t = 100(n - 1)/R
= 100(5 - 1)/10
= 100*4/10
= 40 years

Q 7 - In how much time would the simple interest on a certain sum be 0.125 times the principal at 10% per annum?

A - 4%

B - 11⁄4%

C - 6%

D - 62⁄3%

Answer : C

Explanation

Let sum be z. Then, S.I. = 0.125z = 1z⁄8 Rate = 10
Time = (100 x z⁄z x 8 x 10) = 5⁄4 years = 11⁄4

Q 8 - Mr. Thomas invested an amount of Rs. 13,900 divided in two different Schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in scheme B?

A - 6500

B - 6400

C - 6800

D - 64505⁄9

Answer : B

Explanation

Let the sum be invested in scheme A be Rs. z and that in scheme B be Rs. (13900 - z)
Then, z x 14 x 2⁄100 + (13900 - z) x 11 x 2⁄100 = 3508
28z -22z = 350800 - (13900 x 22) = 6z = 45000 = x = 7500
sum invested in scheme B = Rs (13900 - 7500) = 6400

Q 9 - What yearly portion will release an obligation of Rs 4600 due in 4 years at 10% p.a. basic hobby?

A - Rs 1200

B - Rs 1100

C - Rs 1000

D - Rs 900

Answer : C

Explanation

Let every portion be Rs x.
Unmistakably, first portion will be paid 1 year.
 This cash will be with the loan specialist for a long time.
 Correspondingly, he will have Rs x for a long time, and Rs x toward the end.
(Measure of Rs x for a long time) + (Amount of Rs x for a long time) + (Amount of Rs x for a long time) + Rs x = 4600.
∴ (x+x*10/100*3) + (x+x* 10/100*2) + (x+x*10/100*1) + x=4600
=> (x+3x/10) + (x+x/5) + (x+x/10) + x =4600
=> (13x/10 + 6x/5 + 11x/10+x) = 4600=> 46x=46000=>x=1000.
Henceforth each installment= Rs.1000
aptitude_simple_interest.htm
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