Aptitude - Squares & Cubes Online Quiz



Following quiz provides Multiple Choice Questions (MCQs) related to Squares & Cubes. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - {(√529*36)/48}*? = 5847.75

A - 346

B - 339

C - 317

D - 325

Answer : B

Explanation

Let { (√529*36)/ 48}*x=5847.75
Then, (23*36/ 34 )*x =5847.75 ⇒ x= 5847.75*4/69 = 23391/69 = 339

Q 2 - √4375/√7 = ?

A - 24.75

B - 27.25

C - 25

D - 35

Answer : C

Explanation

√4375/√7 = √4375/√7 = √625 = 25

Q 3 - if √4ⁿ =1024, then the value of n is:

A - 5

B - 8

C - 10

D - 12

Answer : C

Explanation

√4ⁿ=1024  =4⁵⇒4ⁿꜘ2 =4⁵ ⇒ n/2 =5 ⇒ n=10

Q 4 - 36.1/102.4 =?

A - 29/32

B - 19/72

C - 19/32

D - 29/62

Answer : C

Explanation

√36.1/102.4  = √361/1024 = √361/ √1024 =19/32

Q 5 - The square root of (0.09+2 *0.21 +0.49) is

A - 0.58

B - 1

C - √21*1/5

D - none of these

Answer : B

Explanation

(0.09+2*0.21+0.49)= (0.3)2+(0.7)2+2*0.3*0.7= (0.3+0.7)2=12=1
∴√ 0.09 +2*0.21+0.49 = √1 =  1

Q 6 - if 52/x=√(169/289), Then the value of x is

A - 52

B - 58

C - 62

D - 68

Answer : D

Explanation

52/x  = √169/289 = 13/17
∴  13x =(52*17) ⇒ x=(52*17)/13 =68

Q 7 - if √1296 = 36 , then the value of (√12.96 + √0.1296 + √0.001296 + √0.00001296 is:

A - 0.39996

B - 3.9996

C - 39.996

D - none of these

Answer : B

Explanation

Given Exp .  = √1296/100 + √1296/10000 +√1296/ 1000000+ √1296/100000000
=(36/10+ 36/100+36/1000+ 36/10000 ) =(3.6+0.36+0.036+0.0036)= 3.9996.

Q 8 - if (5+ 2√3)/(7+ 4 √ 3) = a+b√3 , then

A - a= -11 , b=-6

B - a= -11, b= 6

C - a= 11, b=-6

D - a= 6, b= 11

Answer : C

Explanation

a+b√3 = (5+2√3/ 7+4√3* 7-4√3/7-4√3)
=  (35-20√3+14√3-24)/(49-48) = 11-6√3

Q 9 - The value of 1/(√2+1)+1/(√3+√2)+1/(√4+√3)...+1/(√121+√120) is

A - √120

B - 12√2

C - 8

D - 10

Answer : D

Explanation

given exp. =1/(√2+1)+1/(√3+√2)+1/(√4+√3)...+1/(√121+√120)
=1/(√2-1)* √2-1)/( √2-1)+1/(√3+√2)* √3-√2/√3-√2+1/(√4+√3)*( √4-√3)/( √4-√3)+?..+1/√121+√120*(√121-√120/√121-√120
= (√2-1)+( √3-√2)+( √4-√3)?..+( √121-√120) =(√121-1)
= (11-1) = 10.  ≤

Q 10 - √0.9 =?

A - 0.3

B - 0.03

C - 0.33

D - 0.94

Answer : D

Explanation

√0.9  = √ 0.94 * 0.94 = 0.94
aptitude_squares_cubes.htm
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