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Volume Calculation - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - A rectangular marble stone 28 cm wide and 5 cm thick weighs 112 kg. In the event that 1 cubic cm of marble measures 25 gm, then the length of given stone is:
Answer : C
Explanation
Let the required length be x cm. Then, its volume = (x*28*5*25/1000) kg = 7x/2 kg ∴ 7x/2= 112 ⇒x= 112*2/7= 32 cm Required length = 32 cm
Q 2 - Half cubic meter of gold sheet is stretched out by pounding in order to spread a region of 1 hectare. The thickness of the sheet is:
Answer : C
Explanation
Area = 1 hectare= 10000m2, Volume = 0.5 m3 Thickness =Volume/Area = (0.5/10000)m =(0.5*100/10000)cm=0.005cm
Q 3 - A corridor is 15m long and 12 m expansive. On the off chance that the aggregate of the zones of the floor and the roof is equivalent to the whole of the ranges of the 4 dividers, the volume of the corridor is:
Answer : C
Explanation
(Lb+Lb) = 2(L+b)*h= 2*Lb = 2(L+b)*h ⇒Lb= (L+b)*h ⇒ (15+12)*h = (15*12) ⇒h = (15*12)/27m = 20/3 m Volume = (L*b*h) = (15*12*20/3) m3= 1200 m3
Q 4 - A wooden box measures 20cm *12cm*10cm. Thickness of the wood is 1cm. Volume of the wood required to make the case is:
Answer : B
Explanation
External volume = (20*12*10) cm3= 2400cm3 Internal length = (20-2) cm =18cm Internal breadth = (12-2) =10 cm Internal height = (10-2) cm =8cm Internal volume = (18*10*8) cm3= 1440cm3 Volume of wood = (2400-1440) cm3= 960cm3
Q 5 - The aggregate surface zone of a solid shape of side 27 cm is:
Answer : C
Explanation
Surface area =6a2= (6*27*27) cm2= 4374cm2
Q 6 - Two solid shapes have their volumes in the proportion 1:27. The proportion of their surface territories is:
Answer : C
Explanation
a3/b3= 1/27= (1/3)3⇒ (a/b) 3= (1/3)3⇒a/b=1/3 ⇒b= 3a S₁/S₂=6a2/6b2= a2/ (3a) 2= a2/9a2= 1/9 = 1:9
Q 7 - The tallness of the barrel is 14 cm and its bended surface range is 264 cm2. The volume of the barrel is:
Answer : B
Explanation
Given h= 14cm and 2πrh= 264 ∴ 2*22/7*r *14= 264 ⇒88r= 264 ⇒r =3 Volume = πr2h = (22/7*3*3*14) cm3= 396 cm3
Q 8 - The number of coins, 1.5cm in distance across and 0.2 cm thick to be softened to shape a right roundabout chamber of stature 10 cm and width 4.5 cm is:
Answer : C
Explanation
For each coin = r =1.5/2cm and h = 0.2 cm Volume of 1 coin = πr2h = (π*1.5/2*1.5/2* 0.2) cm3 =( π*15/2*15/2*2*1/1000)cm3= 9π/80 cm3 For given cylinder, R= 4.5/2 cm and H= 10 cm Volume= πR2H= (22/7*4.5/2*4.5/2* 10*1/100) cm3 = (π*45/2*45/2*10*1/100) = 45*9π/8 cm3 Number of coins= (45*9*π/8*80/9π) = 450
Q 9 - Two barrel have break even with volumes and their statures are in the proportion 1:3. The proportion of their radii is
Answer : D
Explanation
Let their radii be R and r and the heights be h and 3h. Then πR2h = πr2*3h⇒ R2/r2 =3 ⇒(R/r) 2 = (√3)2 ⇒R/r= √3/1 = 3/√3 ∴ R: r = 3:√3
Q 10 - In the event that the sweep of a circle is multiplied, its surface region will increment by:
Answer : C
Explanation
Let, original radius=r. Then surface area= 4πr2 New radius= 2r. New surface area = 4π (2r) 2= 16πr2 Increase % in surface areas = (12πr2/4 πr2*100) %= 300%