Aptitude - Questions & Answers

Progression - Online Quiz

Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Progression. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - The twelfth term of the A.P. 14, 9, 4, - 1, - 6....is:

Answer : D

Explanation

 Here a = 14, d = (9 - 14) = -5.
∴ T₁₂ = a + (12 -1) d = a + 11d = 14 + 11 * (-5) = -41.

Q 2 - What number of numbers arrive somewhere around 10 and 200 which are precisely separable by 7?

Answer : D

Explanation

Requisite numbers are 14, 21, 28, 35 .., 196.
This is an A.P. in which a = 14 and d = 7
a +(n-1) d = 196 ⇒  14+(n-1)*7 =196
= (n-1)*7 = 182 ⇒ (n-1) = 26 ⇒ n = 27.

Q 3 - What number of products of arrive between the whole numbers 15 and 105, both comprehensive?

Answer : B

Explanation

Requisite no. are 15, 18, 21, 24, 105.
Here a = 15 and d = (18-15) = 3
Let their number be n. Then,
a + (n-1) d =105 ⇒ 15+ (n-1)*3 = 105
⇒ a+ (n-1) d = 105 ⇒ 15+ (n-1)*3 = 105
⇒ (n-1)*3 = 90   ⇒ n-1 =30 ⇒ n = 31

Q 4 - (45+46+47....+113+114+115)?

Answer : D

Explanation

Here a=45, d =1 and L=115.
A+ (n-1) d = 115 ⇒ 45+ (n-1) *1 = 115
(n-1 ) = 70 ⇒ n = 71
Sum = n/2 * (a+L) = 71/2 * (45 +115) = 71/2 *160 = (71 *80) = 5680.

Q 5 - The total of initial 20 odd regular numbers is:

Answer : C

Explanation

Sum = (1+3 +5+7+...to 20 terms
Here a = 1, d = (3-1) =2 and n = 20.
∴ Sṇ = n/2 {2a + (n-1) d} =20/2 *{2*1+ (20-1)*2} =10*40=400.

Q 6 - What number of term of the series 3,9,27 ... will mean 363?

Answer : A

Explanation

Given series is a G.P. in which a =3, r= 3 and Sn =363
∴ Sn = a (rⁿ-1)/(r-1) ⇒ 3*(3ⁿ-1)/ (3-1) = 363 ⇒ 3ⁿ-1 = 363*2/3 = 242
3ⁿ= 243 = 3⁵⇒ n =5

Q 7 - The whole (1+1/2+1/4+1/8+1/16+..... =?

Answer : A

Explanation

This is an infinite G.P in which a =1 and r = 1/2
Sum of infinite G.P. = a/ (1-r) = 1/ (1-1/2) =2

Q 8 - A clock hums 1 time at 1o, clock, 2 times at 2o, clock, 3 times at 3o, clock etc. What will be the aggregate quantities of hums in a day?

Answer : C

Explanation

Total number of buzzes =2 (1+2+3+..........+12).
This is an A.P. in which a=1, d=1, n = 12 and L = 12.
(1+2+3+ .........+12) = 12/2* (1+12) = 78.
∴ Total number of buzzes = (2 * 78) = 156.

Q 9 - (14² +15² +......+30²) =?

Answer : D

Explanation

We know that (1²+2²+3²+... +a²) = {n(n+1)(2n+1)}/6
Given Exp. = (1²+2²+...+13²+14²+??+30²)-(1²+2²+...+13²)
= (30*31*61)/6 - (13*14*27)/6 = (9455- 819) = 8636

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