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Progression - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Progression. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Answer : A
Explanation
Here a = 4, d = (9/2-4) = 1/2 T₁0₅ = a+(105-1)*d=4+104*1/2=4+52=56.
Q 2 - What number of numbers arrive somewhere around 10 and 200 which are precisely separable by 7?
Answer : D
Explanation
Requisite numbers are 14, 21, 28, 35 .., 196. This is an A.P. in which a = 14 and d = 7 a +(n-1) d = 196 ⇒ 14+(n-1)*7 =196 = (n-1)*7 = 182 ⇒ (n-1) = 26 ⇒ n = 27.
Q 3 - On the off chance that the tenth term of the succession, a - b, a-2b, a-3b ...is 20 and its twentieth term is 10, then its xth term is:
Answer : D
Explanation
This is an A.P. in which A = a and d = (a-b) -a = -b T₁₀ = 20 ⇒ a+9d = 20 ⇒ a+9*)-b) =20⇒a-9b=20 ... (i) T₂₀ =10⇒ a+19d = 10 ⇒ a+19*(-b) =10⇒a-19b=10 ... (ii) On subtracting (ii) from (i) we get 10b = 10 ⇒ b=1 Putting b= 1 in (i) we get a-9*1=20 ⇒ a =29. ∴ xth term = a + (x-1) *d=29+ (x-1) * (-b) = 29 + (x-1) * (-1) = (30-x).
Answer : D
Explanation
This is an A.P. in which a = 2 and d = (5-2) =3. ∴ Next number= (8+3) =11.
Answer : D
Explanation
Sum = 75+76+77+...+97. Here a =75, d = (76-75) =1 Let the number of terms be n. Then, A+ (n-1) d =97⇒ 75 + (n-1)*1 =97 ⇒ (n-1) = 22 ⇒ n= 23. ∴ Sum = 23/2 (75 + 97) = (23/2 *172) = (23 *86 ) = 1978.
Q 6 - The third term of a geometrical progression is 4. The result of initial 5 terms is:
Answer : C
Explanation
Let the first term be a and common ratio r. Then ar = 4 Product of 5 first term = a* ar*ar2*ar3 *ar⁴ *= a*r⁴ = (ar2)⁵ = 4⁵
Q 7 - Three numbers are in G.P. Their whole is 28 and item is 512. The numbers are:
Answer : C
Explanation
Let the number be a/r, a, ar. Then, a/r* a*ar = 512 ⇒ a3 =83 ⇒ a =8 8/r+8+8r =28 ⇒ 8/r +8r =20 ⇒ 2/r+2r =5 ⇒ 2r2-5r+2 =0 ⇒ 2r2-4r-r+2 =0 ⇒ 2r (r-2)- (r-2)=0 ⇒ (r-2)(2r-1) =0 ⇒r = 2 or r = 1/2 Numbers are 4,8, 16.
Q 8 - A man heaps logs of wood so that the top layer contains one log and every lower layer has one more than the layer above. In the event that there are 15 layers, the aggregate number of logs will be:
Answer : B
Explanation
Total number of logs = 1+2+3+...+15. This is an A.P. in which a =1, d =1 and n= 15. Sn = n/2(a+1) = 15/2 (1+15) =120
Answer : D
Explanation
We know that (13+23+33+??+n3) = {n (n-1)/2)2
∴ (13+23+33+?..+153) = (15*16/2)2 = (120)2 = 14400.3