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Aptitude - Time & Work Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Simple Interest. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - Kamal can do a work in 15 days. Bimal is half more proficient than kamala. The no. of days, Bimal will take to do likewise bit of work, is
Answer : A
Explanation
Kamal 1 day work=1/5. Bimal 1 days work=150% of 1/15=150/100*1/15 =1/10. ∴Bimal can finish the work in 10 days.
Q 2 - A and B together can finish a bit of work in 12 days, B and C can do it in 20 days and C and A do it 15 days. A, B and C together can finish it in
Answer : C
Explanation
(A+B) 1days works =1/12, (B+C) 1days work =1/20, (C+A) 1 days work=1/15. 2(A+B+C) 1days work = (1/12+1/20+1/15) = (5+3+4)/60=12/60=1/5. ⇒ (A+B+C) 1 days works=1/10. ∴A, B and C together can do it in 10 days
Q 3 - A can do 1/3 of a work in 5 days and B can do 2/5 of the work in 10 days. In how long both A and B together can take the necessary steps?
Answer : C
Explanation
1/3 work is done by A in 5 days. Whole work will be done by A in 15 days. 2/5 work is done by B in 10 days. Whole work will be done by B in (10*5/2) day?s i.e 25 days (A+B) 's 1 days work = (1/15+1/25) = 8/75 ∴A and B can do the work in 75/8 days
Q 4 - A can do a bit of work in 10 days and B can do it in 20 days. They begin the work together . Be that as it may, following 5 days, A leaves off. B will do the remaining work in
Answer : A
Explanation
(A+B)'s 5 days work = 5(1/10+ 1/20) = 3/4 ; remaining work = (1- 3/4) = 1/4 1/20 work is done by B in 1 day. 1/4 work is done B in (20* 1/4) = 5 days
Q 5 - A certain no. of men finishes a bit of work in 60 days. On the off chance that there were 8 men more work could be done in 10 days less. What number of men arrived initially?
Answer : B
Explanation
Let there be x men originally. X man finish the work in 60 days and (x+8) finish it in 50 days. X man finish the job in 60 days. ⇒ 1 man can finish it in 50 (x+8) days. ∴ 60 x = 50(X+80 ⇒10 x= 400 ⇒x = 40 Hence, there were 40 men originally.
Q 6 - 9 men working 7 hours a day can finish a bit of work in 15 days. In how long can 6 men functioning for 9 hours a day, complete the same bit of work?
Answer : D
Explanation
(9*7) men working 1 hr a day can finish the work in 15 days. 63 men finish it in 15 days. 1 man can finish it in (15*63) days. (6*9) men can finish it in (15*63)/ (6*9) days = 35/2 days
Q 7 - If 5 men or 9 ladies can complete a bit of work in 19 days, 3 men and 6 ladies will do likewise work in
Answer : D
Explanation
5 men 1 day work = 1/19 ⇒ 1 man's 1 day work = 1/95 9 women 1 day work = 1/19 ⇒1 women 1 day work = 1/171 (3 men + 6 women) 1 day work = (3/95 + 6/171) = (27+30)/855 = 57/ 855 = 1/15 ∴ 3 men and 6 women can finish the work in 15 days.
Q 8 - 8 kids and 12 men finish a sure bit of work in 9 days. In the event that every youngster takes double the time taken by a men to complete the work, in how long will 12 men complete the same work?
Answer : D
Explanation
2 children = 1 man ∴ (8 children + 12 man) = 16 men Let the required number of days be x. Less man, more days 12: 16:: 9: x ⇒x = 16*9/12 = 12 days
Q 9 - A can do 1/4th some portion of the work in 10 days, B can do 40% of the work in 40 days and C can do 1/3 rd of the work in 13 days. Who will finish the work first?
Answer : C
Explanation
1/4th of the work is done by A in 10 days. Whole work will be done by A in (10*4/1) = 40 days 40/100 of the work is done by B in 40 days. Whole work will be done by B in (40*5/2) = 100 days 1/3 of the work is done by C in 13 days. Whole work will be done by C in (13*3/1) = 39 days Hence, C will complete the work first.
Q 10 - A man, a ladies and a kid can finish a vocation in 3 days, 4 days and 12 days individually. What number of young men must help 1 man and 1 lady to finish the occupation in 1/fourth of the day?
Answer : D
Explanation
1 man 1 days work =1/3,1 woman 1 days work=1/4,1 boy 1 day work=1/12. 1 man 1/4 day work= (1/3*1/4) =1/12, 1 woman 1/4 day work work= (1/4*1/4) =1/6. 1 boy 1/4 day work = (1/12*1/4) =1/48. Let (1 man +1 woman + x boys) work=1⇒1/12+1/16+x/48=1⇒7+x=48⇒x=41.