Aptitude - Ratios Online Quiz



Following quiz provides Multiple Choice Questions (MCQs) related to Ratios. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - Rs.11256 is divided among X,Yand Z so that X may receive 1/3 as much as Y and Z together receive Y receives 1/5 of what X and Z together receive. The share of X is more than that of Y by:

A - 938

B - 586

C - 1153

D - 1236

Answer : A

Explanation

X = 1/3(Y+Z) => Y+Z = 3X
=>X+Y+Z = 11256
=> 4X = 11256
=> X = 2814
 Again, Y = 1/5(X+Z) => X+Z = 5Y
=> 6Y = 11256
=>Y = 1876
Then X's share is more than that of Y by Rs. (2814-1876) =938

Q 2 - Rs. 960 was divided among three sons Qavi, Shafi and Rafi. If each of them had received Rs 45 less, their shares would have been in the ratio of 3:5:7. What was the amount received by Qavi?

A - 275

B - 260

C - 320

D - 210

Answer : D

Explanation

Total =Rs.960
If each of them receives Rs.45 less then 960-(45*3) =825
Ratio being 3:5:7
=>3x+5x+7x=825
=>x=55
Qavi's amount = (3x) +45=(3*55)+45=Rs.210

Q 3 - If 15% of A =20% of B , then A:B =?

A - 3:4

B - 4:3

C - 17:16

D - 16:17

Answer : B

Explanation

15/100 a = 20/100 b
=> 15 A = 20 B
=>A/B = 20/15 = 4/3
Thus A:B =4 :3

Q 4 - If 2A =3B and 4B=5C,then A:C=?

A - 3:4

B - 15:8

C - 8:15

D - 4:3

Answer : B

Explanation

2A =3B thus A/B=3/2 and 4B=5C thus B/C = 5/4 
∴  A/C=(A/B*B/C)
= (3/2*5/4) = 15/8 A:C =15:8.

Q 5 - Which of the following function can be used to get an array in the reverse order?

A - array_reverse()

B - array_search()

C - array_shift()

D - array_slice()

Answer : A

Explanation

array_reverse(): Returns an array in the reverse order.

Q 6 - In a class, the no. of young women is 20% more than that of the young fellows. The class' quality is 66. If 4 more young women are admitted to the class, what will be the no's extent of young fellows to that of the young women?

A - 1:2

B - 1:4

C - 3:4

D - 3:5

Answer : C

Explanation

Let the number of boys be x.
Then the no. of girls = 120% of x = (120/100 *X)= 6X/5 .
X+6x/5 =66 
=> 5x+6x=330
 => 11x= 330  
=> x= 3
 Now, the no. of boys= 30 , no. of girls =[6/5*30 +4]=40
 Now the ratio of boys and girls = 30/40 = 3/4 =3:4

Q 7 - What ought to be added to each of the four numbers 6, 14, 18, 38 to make them corresponding?

A - 1

B - 2

C - 3

D - 4

Answer : B

Explanation

Let the number to be added be x. Then,
6+X/14+x=  18+x/38+x
=>  (6+x) (38+x)= (14+ x) (18 +x)
=>  228 +44x+x<sup>2</sup> = 252+32x+x<sup>2</sup>
= 12x=24 
=>  x=2 .
∴ the required number is 2.

Q 8 - Rs. 680 is separated among A, B, C such that A gets 2/3 of what B gets and B gets 1/4 of what C gets. At that point their shares are separately:-

A - 75, 325, 280

B - 80 ,120, 480

C - 90 ,210, 380

D - 100, 200, 380

Answer : B

Explanation

Suppose C gets Rs. x. then B gets Rs. x/4 and gets Rs. (2/3*x/4)= x/6.
∴x/6+x/4+x=680
=>2x+3x+12x=8160
=> 17x= 8160
=> x=480
∴ A gets rs. 80, B gets rs. 120 and C gets rs. 480

Q 9 - Some cash is isolated among A, B and C in a manner that 5 times An offer ,3 times of B's offer and 2 times C offer are all equivalent . The proportion between the offer of A, B, c is:

A - 5:3:2

B - 2:2:5

C - 15:10:6

D - 6:10:15

Answer : D

Explanation

Let 5A= 3B= 2C=k. Then,
A = k/5, B = k/3 and C = k/2
∴ A:B:C =k/5 :k/3:k/2 =6:10:15.

Q 10 - A and B are two compounds of gold and copper arranged by blending metals in the extent 7:2 and 7:11 separately. In the event that the equivalent amounts of the combination are dissolved to frame a third amalgam C, the extent of gold and copper In C will be:

A - 5:9

B - 5:7

C - 7:5

D - 9:5

Answer : C

Explanation

Gold in C=(7/9+7/18)=21/18=7/6.
Copper in C=(2/9+11/18)=15/18=5/6.
∴Gold:Copper=7/6:5/6=7:5.
aptitude_ratios.htm
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